Asked by physiclover
A ball is tossed vertically upwards with a speed of 5.0 m s–1. After how many seconds will the ball return to its initial position?
plz help !
plz help !
Answers
Answered by
bobpursley
hf=hi+vi*t+1/2 g t^2
g=-9.8
0=0+5t-4.8t^2
that is a quadratict equation, use the quadratic formula to find t.
g=-9.8
0=0+5t-4.8t^2
that is a quadratict equation, use the quadratic formula to find t.
Answered by
bobpursley
or, solve it by factoring.... ;)
Answered by
Henry
V = Vo + g*Tr.
0 = 5 + (-9.8)Tr,
Tr = 0.51 s. = Rise time.
Tf = Tr = 0.51 s. - Fall time.
Tr+Tf = 0.51 + 0.51 = 1.02 s. = Return time.
0 = 5 + (-9.8)Tr,
Tr = 0.51 s. = Rise time.
Tf = Tr = 0.51 s. - Fall time.
Tr+Tf = 0.51 + 0.51 = 1.02 s. = Return time.