Asked by Gianna
A ball is tossed up in the air at an angle of 70 degrees with the horizontal and with an initial velocity of 36 ft/sec. What is the position of the ball 1 second after it is released? When will the ball hit the ground? What is the maximum height the ball will reach? How far in a horizontal direction will the ball travel?
Answers
Answered by
Steve
the velocity has two components:
x: 36 cos70° = 12.31
y: 36 sin70° = 33.83
now recall that the x-speed is constant, and the height
y = 33.8t - 16t^2
now solve for the various requirements
x: 36 cos70° = 12.31
y: 36 sin70° = 33.83
now recall that the x-speed is constant, and the height
y = 33.8t - 16t^2
now solve for the various requirements
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