A ball thrown up is caught by thrower 6 sec after start. The height to which the ball has risen is (g=10 m/s2)

Answer 1

so, it took 3 seconds to go up, and 3 to come down. So, with initial velocity v,

v-10*3 = 0
v = 30

h = 30t-5t^2
Now plug in t=3