Asked by Pankaj gangurde sir
A ball thrown up is caught by thrower 6 sec after start. The height to which the ball has risen is (g=10 m/s2)
Answers
Answered by
Steve
so, it took 3 seconds to go up, and 3 to come down. So, with initial velocity v,
v-10*3 = 0
v = 30
h = 30t-5t^2
Now plug in t=3
v-10*3 = 0
v = 30
h = 30t-5t^2
Now plug in t=3
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