Asked by anon
a kayaker paddles across a river at 4.2 m/s at an angle of 73 degrees northeast of the shoreline behind her. The river has a current of 2.4 m/s east acting separately from the motion of the kayaker. What is the kayaker's resultant velocity?
Answers
Answered by
bobpursley
paddling across: 4.2cos73
paddling up river:4.2sin73
current down river:2.4
resultant velocity: sum of those
speed=sqrt(4.2^2cos^273+(4.2sin73-2.4)^2)
direction: arctan Ncomponent/Ecomponent
= arctan(4.2cos73/(4.2sin73-2.4) )
paddling up river:4.2sin73
current down river:2.4
resultant velocity: sum of those
speed=sqrt(4.2^2cos^273+(4.2sin73-2.4)^2)
direction: arctan Ncomponent/Ecomponent
= arctan(4.2cos73/(4.2sin73-2.4) )
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