Asked by John
A kayaker paddles upstream for 1.5 hours then turns his kayak around and returns to his tent in 1 hour. He travels 3 miles each way. What is the rate of the rivers current?
Answers
Answered by
Damon
speed up = u -c
speed down = u+c
d = speed * time
3 = (u-c)1.5
3 = (u+c)1
1.5 u - 1.5 c = 3
1.5 u + 1.5 c = 4.5
--------------------- add
3 u = 7.5
u = 7.5/3
3 = 7.5/3 + c
c = (9-7.5)/3 = 2.5/3 = .83333333333333333333333333
speed down = u+c
d = speed * time
3 = (u-c)1.5
3 = (u+c)1
1.5 u - 1.5 c = 3
1.5 u + 1.5 c = 4.5
--------------------- add
3 u = 7.5
u = 7.5/3
3 = 7.5/3 + c
c = (9-7.5)/3 = 2.5/3 = .83333333333333333333333333
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.