Asked by Tim

A kayaker paddles with a power output of 50.0 W to maintain a steady speed of 1.30 m/s. Calculate the resistive force exerted by the water on the kayak. If the kayaker doubles her power output, and the resistive force due to the water remains the same, by what factor does the kayaker's speed change?
Answered by Anonymous
Well the kayaker is probably a robot if it has an exact power output, so just change the settings to measure the speed of the water that's passing.
two times.
Answered by drwls
Since power = (resistive force) x (speed), the resistive force is 50 W/(1.3 m/s) = 38.5 N... which is about 8.5 pounds

If the resistive force stayed the same (which it won't), power would be proportional to speed.
Answered by HAMMADI
BRUHH, HOW DOES A ROBOT HAVE A OIUTPUT WTF IS THIS CODING???? DONT YOU KNOW HOW TO CODE?? WHY SO SERIOUS. AN WE TALK ABOUT THE ECONOMICAL AND POLITICAL STATE OF THE WORK RN LIKE BRUIHHHH
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