Question

A kayaker paddles due north at 2 m/s. The river the kayaker is paddling in flows towards the east at 1 m/s. After 5 seconds of paddling, how far is the kayaker from where she started in m?
v=sqrt(v₁²+v₂²) = sqrt(4+1) =2.236 m/s
s=vt=2.236•5=11.18 m

Related Questions

A kayaker needs to paddle north across a 85-m-wide harbor. The tide is going out, creating a tidal... a kayaker paddles across a river at 4.2 m/s at an angle of 73 degrees northeast of the shoreline beh... A kayaker paddles upstream from camp to photograph a waterfall and returns. The kayaker's speed whil...