Ask a New Question

Question

A kayaker needs to paddle north across a 85-m-wide harbor. The tide is going out, creating a tidal current that flows to the east at 2.0 m/s. The kayaker can paddle with a speed of 3.0 m/s. Find the angle West of North he needs to travel and the time it takes him to cross.

Thanks!
9 years ago

Answers

Chanz
tan-1(2/3)
t = x/v = 85/3
9 years ago

Related Questions

A kayaker paddled 2 hours with a 6 mph current in a river. The return trip against the same current... A kayaker paddled 2 hours with a 6 mph current in a river. The return trip against the same current... A kayaker paddles with a power output of 50.0 W to maintain a steady speed of 1.30 m/s. Calculate th... If a kayaker's speed while traveling upstream is 7 miles per hour and downstream is 4 miles per hour... A kayaker paddles due north at 2 m/s. The river the kayaker is paddling in flows towards the east at... A kayaker paddles across a river at a constant speed of 4 miles per hour and a bearing of N 60 degre... A kayaker needs to paddle north across a 85 m wide harbor. The tide is going out, creating a tidal c... A kayaker paddles upstream for 1.5 hours then turns his kayak around and returns to his tent in 1 ho... A kayaker paddles at 4.0 m/s in a direction 30° south of west. He then turns and paddles at 3.7 m/s... A kayaker travels x miles per hour downstream for 2 hours. On the 4-hour return trip, the kayaker t...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use