Question
A body is projected with an initial velocity 300m\s at an angle 60 with the vertical;determine
:1.the
velocity at the maximum height
2.The maximum height reached
:1.the
velocity at the maximum height
2.The maximum height reached
Answers
bobpursley
vertical velocity initial:
300sin60
at top, velocity is only horizontal
vh=300cos60
at top
1/2 m vi'^2=mgh
h= (300sin60)^2/9.8 METERS
300sin60
at top, velocity is only horizontal
vh=300cos60
at top
1/2 m vi'^2=mgh
h= (300sin60)^2/9.8 METERS