Question
a body projected with velocity 30m/s an angle 30¡ã with horizontal maximum height attained by he object is.........?
Answers
Anonymous
well, the upward component is
15 m/s, so the height is
h(t) = 15t - 4.9t^2
So, just find the vertex of that parabola.
15 m/s, so the height is
h(t) = 15t - 4.9t^2
So, just find the vertex of that parabola.
Ravi
2sin-ecos
Kingsley wale
A mass is launched at 30 degree to the horizontal with a speed 25 metre per second. What is the maximum height obtained??