Question

a body is projected horizontally with a velocity of 80m/s from the top of a tower 160m above the ground. find the time of flight,range,velocity at which the body strikes the ground

Answer 1

time of flight (time to fall):
hf=hi+vi*t-1/2 9.8 t^2. In the vertical, vi is zero, hi=160, hf=0 solve for t.

range=vi*timeofflight

finalvelocity:
vertical: vf=g*timeofflight downward
horizontal=80m/s

Vfinal=vf downward + vh (parallel to ground) this is a vector equation

Answer 2

The speed of projection is 40m/s upward.The negative value gives the speed at which the dody again arrives at the level of projection

Answer 3

U2 Sin 2a
=g
=34.66m