Asked by Ja'Terra
A ball is projected horizontally from the edge
of a table that is 1.2 m high, and it strikes the
floor at a point 1.11 m from the base of the
table.
The acceleration of gravity is 9.8 m/s2 .
What is the initial speed of the ball?
Answer in units of m/s
of a table that is 1.2 m high, and it strikes the
floor at a point 1.11 m from the base of the
table.
The acceleration of gravity is 9.8 m/s2 .
What is the initial speed of the ball?
Answer in units of m/s
Answers
Answered by
drwls
Using the height H of the table, compute the time t required to hit the ground.
t = sqrt(2H/g)= 0.495 s
Initial speed =
= horizontal V component = (1.11 m)/t
t = sqrt(2H/g)= 0.495 s
Initial speed =
= horizontal V component = (1.11 m)/t