Ask a New Question

Question

A ball is projected horizontally from the edge of a table that is 1.14 m high, and it strikes the floor at a point 1.40 m from the base of the table. It's initial velocity is 2.9 m/s. How high is the ball above the floor when its velocity vector makes a 43.6o angle with the horizontal?
9 years ago

Answers

Henry
Xo = 2.9 m/s.

Tan 43.6 = Y/Xo = Y/2.9.
Y = 2.9*Tan 43.6 = 2.76 m/s.

V^2 = Vo^2 + 2g*d = 2.76^2.
0 + 19.6d = 7.63, d = 0.389 m.

h = 1.14 - 0.389 = 0.751 m. Above
the floor.




9 years ago

Related Questions

a ball is projected horizontally from the edge of a table that is 0.433m high, and it strikes the f... A ball is projected horizontally from the edge of a table that is 1.2 m high, and it strikes the f... A ball is projected horizontally from the edge of a table that is 1.2 m high, and it strikes the f... A ball is projected horizontally from the edge of a table that is 1.15 m high, and it strikes the fl... A ball is projected horizontally from the top of a 98m high cliff with an initial speed of 14.4 m/s.... A ball is projected horizontally with a initial velocity 8m/s .Find its position and velocity after... A ball is projected horizontally from the edge of a table that is 1.00 m high, and it strikes the fl... A ball is projected horizontally from the top of a vertical cliff 40m high at a velocity of 20ms-ยน... A ball is projected horizontally from the top of a vertical cliff 40m high at a volocity of 20ms cal...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use