Asked by praizefavor
a body is projected horizontally with a velocity of 20m/s from height of a tower 160m above the ground calculate the time of flight distance from the foot of the tower to where the object land
Answers
Answered by
Steve
how long does it take to fall 160m? The horizontal speed does not affect that.
4.9t^2 = 160
Now, the horizontal speed does not change, so the body travels
20t meters
4.9t^2 = 160
Now, the horizontal speed does not change, so the body travels
20t meters
Answered by
praizefavor
what if i said it is u=20 h=160
20/10=2m/s 160/10=16
t=8m/s
1.time of flight =8m/s 16/2=8m/s
2.distance=20*10=200/10=2
distance
=2*10/10=2mls
H=8m/s
V=2m/s
thats how i got my answer collect me if am worng
20/10=2m/s 160/10=16
t=8m/s
1.time of flight =8m/s 16/2=8m/s
2.distance=20*10=200/10=2
distance
=2*10/10=2mls
H=8m/s
V=2m/s
thats how i got my answer collect me if am worng
Answered by
Anonymous
H:160m
t:T. ay:9.8
Uy : 0
H: uy*t+1/2ay*t*t
160=0*T+1/2 * 9.8*TT
160=1/2*9.8*TT
160*2/9.8=TT
√160/√4.9=T
4√10/7=T
t:T. ay:9.8
Uy : 0
H: uy*t+1/2ay*t*t
160=0*T+1/2 * 9.8*TT
160=1/2*9.8*TT
160*2/9.8=TT
√160/√4.9=T
4√10/7=T
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.