Asked by ROKEEB
A body is projected horizontally with a velocity of 80m/s from the top of a tower 160m above the ground (given that g=10m/s2).Find (1)time of flight. (2)Range
Answers
Answered by
bobpursley
time of flight:
h=1/2 g t^2
t=sqrt (2h/g)
horizontal range=80*t
h=1/2 g t^2
t=sqrt (2h/g)
horizontal range=80*t
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