Asked by Jacke
What is the theoretical yield of Fe2(SO4)3 if 20.00 g of FePO4 reacts with an excess of Na2SO4?
Answers
Answered by
DrBob222
Those don't react but if they did it would be this.
2FePO4 + 3Na2SO4 ==> 2Na3PO4 + Fe2(SO4)3
mols FePO4 = grams/molar mass = ?
Then using the coefficients in the balanced equation, convert mols FePO4 to mols Fe2(SO4)3. That's
mols FePO4 x (1 mol Fe2(SO4)3/2 mols FePO4) = ?mols FePO4 x (1/2) = ?
Then grams Fe2(SO4)3 = mols x molar mass. That is the theoretical yield.
2FePO4 + 3Na2SO4 ==> 2Na3PO4 + Fe2(SO4)3
mols FePO4 = grams/molar mass = ?
Then using the coefficients in the balanced equation, convert mols FePO4 to mols Fe2(SO4)3. That's
mols FePO4 x (1 mol Fe2(SO4)3/2 mols FePO4) = ?mols FePO4 x (1/2) = ?
Then grams Fe2(SO4)3 = mols x molar mass. That is the theoretical yield.
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