Asked by Anonymous

What is theoretical yield of Cr2O3 if the amount of Cr is 0.0382mol and the actual yield of Cr2O3 is 0.0186mol?
4Cr + 3O2 → 2Cr2O3

Can you please tell me how to solve for it? Thankk you so much!

Answers

Answered by DrBob222
0.0382 mols Cr x (2Cr2O3/4 Cr) = 0.0382/2 = 0.0191
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