Asked by Taylor
What is the theoretical yield of PbI2 with 25.0 g of Pb(NO3)2?
Answers
Answered by
DrBob222
Actually you need a reaction to be certain but in a pinch you can do
25.0 g Pb(NO3)2 x [molar mass PbI2/molar mass Pb(NO3)2] = ??g PbI2.
25.0 g Pb(NO3)2 x [molar mass PbI2/molar mass Pb(NO3)2] = ??g PbI2.
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