What is the theoretical yield in grams of the precipitate starting with 1.250 moles of iron ions (charge is +3) and 60.00 grams of hydroxide ions?

Answer 1

Fe^+3 + 3OH^- ==> Fe(OH)3(s)

This is a limiting reagent problem.
Convert 60.00 g OH^- to mols.
a. Determine mols Fe(OH)3 produced by using 1.25 mols Fe^+3.
b. Determine mols Fe(OH)3 produced by using 60/17 mols OH^-.
c. The correct answer will be the smaller of the two answers in a or b. That material is the limiting reagent. Then convert the mols Fe(OH^-)3 produced to grams. That is the theoretical yield.
Then convert mols