Asked by Kenzie

C6H12 (g) + 9 O2 (g) ----> 6CO2 (g) + 6 H2O(g)

How many L of oxygen gas is needed if we produce 5.66 L of CO2?
Answered by DrBob222
With all gases one can use volume in L directly as mols as a short cut.
5.66 L CO2 x (9 O2/6 CO2) = ?
Answered by Anonymous
3.77 L of o2
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