Okay, this is what I think... it seems to be too easy.
So the reaction produces 6 moles of CO2 and 6 moles of H2O, that mean they have a ratio of 1 to 1. In other word, when you have 174 moles of H2O, then you'll also have 174 moles of CO2... so there isn't really any calculation you need to do in this problem.
based on the balanced eq: c6h12+9O2->6CO2+6H2O
calculate the molecules of CO2 formed when 174 molecules of H20 form.
im not exactly sure how to start this problem.
2 answers
One slight problem.
174 molecules is not 174 moles.
174 molecules x (1 mol/6.02 x 10^23 molecules) = # mols CO2 produced if you want to go that way. Otherwise, the reasoning is sound; therefore, 174 molecules of water will be formed when 174 molecules of CO2 are formed.
174 molecules is not 174 moles.
174 molecules x (1 mol/6.02 x 10^23 molecules) = # mols CO2 produced if you want to go that way. Otherwise, the reasoning is sound; therefore, 174 molecules of water will be formed when 174 molecules of CO2 are formed.
1 answer