Asked by Kat
Cyclohexane, C6H12, a hydrocarbon, can isomerize or change into methylcyclopentane, a compound of the same formula (C5H9CH3) but with a different molecular structure.
The equilibrium constant is 0.12 at 25°C. If you had originally placed 0.036 mol of cyclohexane in a 1.0 L flask, what would be the concentrations of cyclohexane and methylcyclopentane when equilibrium is established?
For [C6H12]?
For [C5H9CH3]?
The equilibrium constant is 0.12 at 25°C. If you had originally placed 0.036 mol of cyclohexane in a 1.0 L flask, what would be the concentrations of cyclohexane and methylcyclopentane when equilibrium is established?
For [C6H12]?
For [C5H9CH3]?
Answers
Answered by
DrBob222
Is this Kc or Kp = 0.12? I will assume it is Kc.
What is the reaction for K. I will assume it is
cyclohexane ==> methyl cyclopentane
K = 0.12 = (mcyp)/(cyh)
Set up an ICE chart.
...........mcyh ==> mcyp
initial....0.036....0
change.....-x.......x
equil.....0.036-x...x
Substitute the equilibrium values into the Kc expression and solve for x.
What is the reaction for K. I will assume it is
cyclohexane ==> methyl cyclopentane
K = 0.12 = (mcyp)/(cyh)
Set up an ICE chart.
...........mcyh ==> mcyp
initial....0.036....0
change.....-x.......x
equil.....0.036-x...x
Substitute the equilibrium values into the Kc expression and solve for x.
Answered by
Anonymous
hjhh
There are no AI answers yet. The ability to request AI answers is coming soon!