Asked by Cece
calculate the delta Hf of c6h12o6 (s) from the following data:
Delta H combustion= -2816 kj/mol
delta Hf of Co2 = -393.5 kj/mol
delta Hf= of H2 O= -285.9kj/mol
Delta H combustion= -2816 kj/mol
delta Hf of Co2 = -393.5 kj/mol
delta Hf= of H2 O= -285.9kj/mol
Answers
Answered by
DrBob222
dH = delta H.
C12H22O11 + 12O2 ==> 12CO2 + 11H2O
dHrxn = (12*dHf CO2 + 11*dHf H2O) - (1*dHf C12H22O11)
Plug in the values and solve for dHf C12H22O11.
C12H22O11 + 12O2 ==> 12CO2 + 11H2O
dHrxn = (12*dHf CO2 + 11*dHf H2O) - (1*dHf C12H22O11)
Plug in the values and solve for dHf C12H22O11.
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