Asked by Samantha
How would you calculate delta H for the following reaction:
2P + 5Cl2 -> 2PCl5
Given:
PCl3 + Cl2 -> PCl5 Delta H=-87.9 kJ
2P + 3Cl2 -> 2PCl3 Delta H=-574 kJ
I have no clue how to do this since I was absent. Can someone help?
2P + 5Cl2 -> 2PCl5
Given:
PCl3 + Cl2 -> PCl5 Delta H=-87.9 kJ
2P + 3Cl2 -> 2PCl3 Delta H=-574 kJ
I have no clue how to do this since I was absent. Can someone help?
Answers
Answered by
DrBob222
Look up Hess' Law.
Multiply equation 1 by 2 and add it to equation 2. Multiply delta H for equation 1 by 2 and add to delta H for equation 2.
Multiply equation 1 by 2 and add it to equation 2. Multiply delta H for equation 1 by 2 and add to delta H for equation 2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.