Question

Calculate the value of T delta S (KJ) of reaction for the equation as written. (It is given that the standard enthalpies (J/K mol)are CH3COOH=159.8, O2=205.138, CO2=213.7, H20=69.91)

CH3COOH(l) + 2 O2(g) --> 2 CO2(g) + 2H2O(l)

Answer 1

Something is not right here. Those aren't the number in my table. I don't have CH3COOH but the others are incorrect.

Answer 2

well those are the numbers that was given to me..but im not sure if its called standard enthalpies ..the number are labeled under a "S" with a subscript 0

Answer 3

S^o is the standard ENTROPY, not enthalpy.

Answer 4

oh sorry my bad...

how would i start this problem?

Answer 5

Look in your problem. There must be a temperature given if you are to calculate TdeltaS.

delta S is calculated by
delta S reaction = (sum of delta S products ) - (sum of delta S reactants). Then T*delta S is just T times that.

Answer 6

my answer is -851.088

is that right?

Answer 7

I can't check the problem because there is no temperature listed in your problem.