Asked by Anonymous

Calculate the value of T delta S (KJ) of reaction for the equation as written. (It is given that the standard enthalpies (J/K mol)are CH3COOH=159.8, O2=205.138, CO2=213.7, H20=69.91)

CH3COOH(l) + 2 O2(g) --> 2 CO2(g) + 2H2O(l)
Answered by DrBob222
Something is not right here. Those aren't the number in my table. I don't have CH3COOH but the others are incorrect.
Answered by Anonymous
well those are the numbers that was given to me..but im not sure if its called standard enthalpies ..the number are labeled under a "S" with a subscript 0
Answered by DrBob222
S<sup>o</sup> is the standard ENTROPY, not enthalpy.
Answered by Anonymous
oh sorry my bad...

how would i start this problem?
Answered by DrBob222
Look in your problem. There must be a temperature given if you are to calculate TdeltaS.

delta S is calculated by
delta S reaction = (sum of delta S products ) - (sum of delta S reactants). Then T*delta S is just T times that.
Answered by Anonymous
my answer is -851.088

is that right?
Answered by DrBob222
I can't check the problem because there is no temperature listed in your problem.
There are no AI answers yet. The ability to request AI answers is coming soon!