Question
to produce 4.00 mole if c6h12 from the following how many grams of c6h6 must you combine
78.12 g/mol c6h6 + 2.02 g/mol h2 = 84.18 g/mol c6h12
78.12 g/mol c6h6 + 2.02 g/mol h2 = 84.18 g/mol c6h12
Answers
DrBob222
C6H6 + 3H2 ==> C6H12
For 4.0 moles C6H12 you must start with 4.0 moles C6H6.
For 4.0 moles C6H12 you must start with 12 moles H2. Here is how I did that.
4.0 moles C6H12 x (1 mol C6H6/1 mol C6H12) = 4 x 1/1 = 4.0
4.0 moles C6H12 x (3 moles H2/1 mol C6H12) = 12.0 moles H2.
If you want grams,
convert to grams.
g = moles x molar mass.
For 4.0 moles C6H12 you must start with 4.0 moles C6H6.
For 4.0 moles C6H12 you must start with 12 moles H2. Here is how I did that.
4.0 moles C6H12 x (1 mol C6H6/1 mol C6H12) = 4 x 1/1 = 4.0
4.0 moles C6H12 x (3 moles H2/1 mol C6H12) = 12.0 moles H2.
If you want grams,
convert to grams.
g = moles x molar mass.