To determine if the ball will clear the sand trap, we need to find the height of the ball when it reaches the nearest edge of the sand trap.
First, we can find the time it takes for the ball to reach the nearest edge of the sand trap. We can use the horizontal component of the initial velocity and the horizontal distance to the sand trap:
Vx = V * cos(angle)
Vx = 135 * cos(22°)
Vx ≈ 126.39 ft/s
Horizontal distance = Vx * t
300 = 126.39 * t
t ≈ 2.37 seconds
Next, we can find the vertical component of the initial velocity:
Vy = V * sin(angle)
Vy = 135 * sin(22°)
Vy ≈ 50.71 ft/s
Now we can find the height of the ball at the nearest edge of the sand trap using the vertical component of the velocity:
y = Vy*t - 0.5*g*t^2
y = 50.71*2.37 - 0.5*32*2.37^2
y ≈ 120.14 feet
Since the height of the ball (120.14 feet) is greater than the 25-foot wide sand trap, the ball will clear the sand trap.