Question
A golf ball is hit with an initial velocity of 140 ft per second at an inclination of 45 degrees to the horizontal. In physics, it is established that the height h of the golf ball is given by the function h(x)=-32x^2/140^2+x,
How far does the golf ball travel before it lands?
How far does the golf ball travel before it lands?
Answers
Steve
just solve for x when h=0.
Clearly, it is only when x=0.
If you mean
h(x)=-32x^2/(140^2+x)
If you meant it as written,
h(x)=-32x^2/140^2 + x = x(1 - 64x/1225)
h=0 when x = 1225/64
Clearly, it is only when x=0.
If you mean
h(x)=-32x^2/(140^2+x)
If you meant it as written,
h(x)=-32x^2/140^2 + x = x(1 - 64x/1225)
h=0 when x = 1225/64