Asked by mu

A golf ball is hit with an initial velocity of 140 ft per second at an inclination of 45 degrees to the horizontal. In​ physics, it is established that the height h of the golf ball is given by the function h(x)=-32x^2/140^2+x,

How far does the golf ball travel before it lands?

Answers

Answered by Steve
just solve for x when h=0.

Clearly, it is only when x=0.

If you mean

h(x)=-32x^2/(140^2+x)

If you meant it as written,

h(x)=-32x^2/140^2 + x = x(1 - 64x/1225)
h=0 when x = 1225/64
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