Ask a New Question

Question

A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. What's the maximum height it will reach?
15 years ago

Answers

MathMate
The vertical component of the velocity is v=50sin(45°).
Ignore air resistance and equate energy:
(1/2)mv² = mgh
h=v²/(2g)
15 years ago

Related Questions

A golf ball is hit with an initial velocity of 50 m/s at an angle of 45 degrees with the horizontal.... A golf ball is hit with an initial velocity of 135 feet per second at an angle of 22 degrees above t... A golf ball is hit with an initial velocity of 135 feet per second at an angle of 22 degree above th... A golf ball is hit with an initial angle of 30.5° with respect to the horizontal and an initial velo... A golf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. How f... A golf ball is hit with an initial velocity of 50m/s at an angle of 25° above the horizontal. A) H... A golf ball is hit with an initial velocity of 50 m/s at an angle of 39 degrees above the horizontal... A golf ball is hit with an initial velocity of 15 meters per second at an angle of 35 degrees above... A golf ball is hit with an initial velocity of 140 ft per second at an inclination of 45 degrees to...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use