Asked by Jennifer
Did I differentiate these two functions correctly?
y=2cos(2x)cos(14x)
y'=-14 sin(14x)2 cos(2x)-4 sin(2x)cos(14x)
y=2[cos 1/2(f1-f2 )x][cos 1/2(f1+f2 )x]
y^'=-[(f1+f2 )/2]sin[(f1+f2 )/2 x]2cos[(f1-f2 )/2 x] - [2(f1-f2 )/2]sin[(f1-f2 )/2 x]cos [(f1+f2)/2 x]
y=2cos(2x)cos(14x)
y'=-14 sin(14x)2 cos(2x)-4 sin(2x)cos(14x)
y=2[cos 1/2(f1-f2 )x][cos 1/2(f1+f2 )x]
y^'=-[(f1+f2 )/2]sin[(f1+f2 )/2 x]2cos[(f1-f2 )/2 x] - [2(f1-f2 )/2]sin[(f1-f2 )/2 x]cos [(f1+f2)/2 x]
Answers
Answered by
Steve
they appear correct