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An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it e...Asked by mb
An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it explodes on a mountainside 42 sec after firing. what is the x-coordinate of the shell where it explodes, relative to its firing point?
An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it explodes on a mountainside 42 sec after firing. What is the y-coordinate of the shell where it explodes, relative to its firing point?
An artillery shell is fired with an initial velocity of 300 m/s at 55 degrees above the horizontal. to clear an avalanche, it explodes on a mountainside 42 sec after firing. What is the y-coordinate of the shell where it explodes, relative to its firing point?
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Answered by
Stephanie
ok, so you have to find the cos of x-axis: v*cos=(300m/s)cos 55 degrees, and then the sin of your y-axis: v*sin= (300m/s)sin 55 degrees. The vx (x-axis)is always constant.
Then you have to use the formula: x=x(i)*t+ 1/2axt^2 to get the x- coordinate, y=y(i)*t +1/2ayt^2. That'll give you the y- coordination. Hope that helps you..Good luck!
Then you have to use the formula: x=x(i)*t+ 1/2axt^2 to get the x- coordinate, y=y(i)*t +1/2ayt^2. That'll give you the y- coordination. Hope that helps you..Good luck!
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