Asked by scarlette abegail
a projectile is fired with an initial velocity of 800 ft/s at a target of 12000 ft downrange and at an elevation of 3000 ft above the ground, neglecting air resistance, determine the angle(s) that can be used to reach the target.
Answers
Answered by
Reed
This looks like a physics question. I never heard of "university of saint la salle" as a School Subject.
Answered by
Steve
well, you know the equation of the altitude of the trajectory is
y = x tanθ - g/(2 v^2 cos^2θ) x^2
So, just solve for θ in
12000tanθ - 9.8/(2(800cosθ)^2) = 3000
θ = 14°
Better check my math.
y = x tanθ - g/(2 v^2 cos^2θ) x^2
So, just solve for θ in
12000tanθ - 9.8/(2(800cosθ)^2) = 3000
θ = 14°
Better check my math.
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