Asked by Anon

A projectile which is fired from the ground with a velocity of 960 ft/sec, at an angle of 30° above the ground, has a height at time t of h(t)=480t–16t2. Find the time when it hits the ground again.
Answered by Anonymous
height has to equal 0 because its hitting the ground
0=480t-16t^2 factor
0=16t(30-t)
so t=0 or 30
0 is when its fired so it must be 30
so it hits the ground again after 30 seconds
Answered by 28.5714
its 5
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