Question
A projectile is fired at an upward angle of 45 degrees from the top of a 265 m cliff with a speed of 350 m/s. What will be it's speed when it strikes the ground below?
Answers
bobpursley
the initial energy is 1/2 m v^2 + mgh
the final energy is 1/2 m vf^2 set them equal.
1/2 m vf^2=1/2 m vi^2 + mg265
solve for Vf
the final energy is 1/2 m vf^2 set them equal.
1/2 m vf^2=1/2 m vi^2 + mg265
solve for Vf
Anonymous
200
OOOOHHHHH ITS AN AVOCADOOOOO
I think it is infinity