Question

A projectile is fired at an angle of 60degree with the horizontal and with the initial velocity 80m/s calculate (a) the time of flight(b)time to reach maximum height(c)it range(d)the velocity of projection 2seconds after been fired

Answer 1

a)T=2u sin60/g=13.85s
b)t=T/2=6.92s
c)R=554.25m

Answer 2

For a, using g = 9.80 m/s^2, I get
T = 2 u sin 60/g = 14.14 s. If I use g = 9.81 m/s^2, I get 14.12 s.

This leads to slightly different answers to b) and c) than were obtained by vishesh

c) Use
R = u cos 60 * T

Answer 3

A projectile is fired from ground level with an initial velocity of 50m/s and an initial angle of 30degree. Assuming g= 9.8 m/s*2, find:
(a) The projectile total time of flight.
(b) The maximum height attained
(c) The total horizontal traveled
(d) The final horizontal and vertical velocities just before it hits the ground