Question
the sum of three intergers is 193.The smaller two are consecutive intergers and the larger two are consecutive even intergers.What are the three intergers?
Answers
wouldn't the smaller two be one apart, and the larger two would be two apart?
so
smallest --> x
second ---> x+1
third ---> x+3
then x + x+1 + x+3 = 193
solve for x
so
smallest --> x
second ---> x+1
third ---> x+3
then x + x+1 + x+3 = 193
solve for x
x+x+1+x+3=193
3x+4=193
-4 -4
3x=189
x=63
3x+4=193
-4 -4
3x=189
x=63
thank you!
3x+4=193 you don't know what x is so you cant go any farther i just got done with this unit
uhmm i think you would subtract 4 from both sides so that would just leave you with 3x
3x+4=193
-4 -4
3x= 189
then you would divide 3 from both sides
which leaves you with 63
x=63 =]
oh and make surewhen you do these promblems you go back and check it
3x+4=193
-4 -4
3x= 189
then you would divide 3 from both sides
which leaves you with 63
x=63 =]
oh and make surewhen you do these promblems you go back and check it
4×4
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