Asked by aitan
find two intergers whose sum 14 and whose product is 48
Answers
Answered by
oobleck
even without doing the algebra, surely you can think of two factors of 48 that add to 14 !!
6*8
But, for a more general solution,
x+y = 14
xy = 48
x(14-x) = 48
x^2 - 14x + 48 = 0
(x-6)(x-8) = 0
...
6*8
But, for a more general solution,
x+y = 14
xy = 48
x(14-x) = 48
x^2 - 14x + 48 = 0
(x-6)(x-8) = 0
...
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