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Three consecutive odd intergers are such that the sum of the squares of the first two integers is 54 more than 20 times the third integer. Determine the three integers.
9 years ago

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Answered by Steve
x^2 + (x+2)^2 = 54+20(x+4)
9 years ago
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Three consecutive odd intergers are such that the sum of the squares of the first two integers is 54 more than 20 times the third integer. Determine the three integers.

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