Asked by San
Calculate the amount (in grams) of Tris Base needed to make 1L of 0.01M Tris buffer?
Tris Base=121.4 g/mol
Tris Base=121.4 g/mol
Answers
Answered by
RCA
M x V = 0.01 mole/liter x 1 liter = 0.01 mole
mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)
mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)
Answered by
RCA
M x V = 0.01 mole/liter x 1 liter = 0.01 mole
mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)
The solution is not really a buffer. There is no pH mentioned in the problem.
mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)
The solution is not really a buffer. There is no pH mentioned in the problem.
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