Question

Calculate the amount (in grams) of Tris Base needed to make 1L of 0.01M Tris buffer?
Tris Base=121.4 g/mol

Answer 1

M x V = 0.01 mole/liter x 1 liter = 0.01 mole

mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)

Answer 2

M x V = 0.01 mole/liter x 1 liter = 0.01 mole

mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)

The solution is not really a buffer. There is no pH mentioned in the problem.