Asked by laura
The amount A, of 70 grams of a certain radioactive material remaining after t years can be found by the equation A=70(0.62)^t. When will 10 grams remain?
Answers
Answered by
Steve
just find t where
70*0.62^t = 10
.62^t = 1/7
t log.62 = log 1/7
t = log(1/7)/log(.62) = 4.07
70*0.62^t = 10
.62^t = 1/7
t log.62 = log 1/7
t = log(1/7)/log(.62) = 4.07
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