Asked by selly
Determine the amount (in grams) of boron that when substitutionally incorporated into 1 kg of silicon will establish a charge carrier density of 3.091×1017 carriers/cm3.
Answers
Answered by
ssb (India)
Answer : 2.4227*10^-3
i.e. 0.002423
i.e. 0.002423
Answered by
c
thanks
Answered by
Jose Violero
Information
density Si=2.33 g/cc
Mw(P)=10.81 g/mole
NA=6.022*10^23 at/mole
V (Si)=1 Kg *1000 g/Kg /(2.33 g/cc = 4.29*10^2 cc
moles B/cc = 3.091*10^17 carriers/cc /6.022*10^23 =5.133*10^-7 moles B/cc
moles B= 5.133*10^-7 moles/cc *4.29*10^2 cc= 2.203*10^-4 moles B
g B= 2.203*10^-4 moles * 10.81 g/mole = 2.4227*10^-3 g
density Si=2.33 g/cc
Mw(P)=10.81 g/mole
NA=6.022*10^23 at/mole
V (Si)=1 Kg *1000 g/Kg /(2.33 g/cc = 4.29*10^2 cc
moles B/cc = 3.091*10^17 carriers/cc /6.022*10^23 =5.133*10^-7 moles B/cc
moles B= 5.133*10^-7 moles/cc *4.29*10^2 cc= 2.203*10^-4 moles B
g B= 2.203*10^-4 moles * 10.81 g/mole = 2.4227*10^-3 g
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