RCA

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To clarify, 100 L weigh 100 kg or 1x10^5 g

M x V = 0.01 mole/liter x 1 liter = 0.01 mole mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit)

M x V = 0.01 mole/liter x 1 liter = 0.01 mole mass (g) = mole x molar mass = 0.01 mole x 121.4 grams/mole = 1.214 grams = 1 gram (corrected to 1 significant digit) The solution is not really a buffer. There is no pH mentioned in the problem.