Asked by Jennifer
Calculate the amount of 6 M nitric acid you need to add to fully react with .5 grams of copper and add a 20 percent excess.
Answers
Answered by
DrBob222
Here is a worked example of a stoichiometry problem such as this. After finding moles HNO3, the M = moles/L will give you volume HNO3, then add 20% excess to that.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
Answered by
Jennifer
I still do not understand.
Answered by
DrBob222
You haven't had time to try yet. Follow the steps one by one. Those instructions, which I wrote, will take you to the answer.
The equation is
3Cu + 8HNO3 ==>3Cu(NO3)2 + 2NO + 4H2O
Check that to make sure it is balanced.
The equation is
3Cu + 8HNO3 ==>3Cu(NO3)2 + 2NO + 4H2O
Check that to make sure it is balanced.
Answered by
Jennifer
It still doesnt make aense because the answer comes out to 240 liters.
Answered by
N
That's not a balanced equation. It should be Cu + 4HNO3 ==>Cu(NO3)2 + 2NO + 2H2O
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