Asked by Amy
solve the equation for the interval
0<x<2pie
cos^2 x + 2cosx + 1 = 0
0<x<2pie
cos^2 x + 2cosx + 1 = 0
Answers
Answered by
Reiny
cos^2 x + 2cosx + 1 = 0 factors to
(cos x + 1)^2 = 0
cos x + 1 = 0
cos x = -1
x = PI
(cos x + 1)^2 = 0
cos x + 1 = 0
cos x = -1
x = PI
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