Asked by NunYa
Which Is equation in slope intercept form for the line passes through (2,8) and is perpendicular to 4x+2y=6
y=-1/2x+7
y=1/2x+7
y=-2x+12
y=2x+4
Love you and thanks for the help
y=-1/2x+7
y=1/2x+7
y=-2x+12
y=2x+4
Love you and thanks for the help
Answers
Answered by
Reiny
sticking with the standard form, if
4x+2y=6 is a line, then a perpendicular line would be
2x - 4y = c
plug in your given point (2,8)
4 - 32 = c
c = -28
new equation:
2x - 4y = -28
x - 2y = -14
now switch to other form
-2y = -x - 14
divide both sides by -2
y = (-1/2)x + 7 , I see that
4x+2y=6 is a line, then a perpendicular line would be
2x - 4y = c
plug in your given point (2,8)
4 - 32 = c
c = -28
new equation:
2x - 4y = -28
x - 2y = -14
now switch to other form
-2y = -x - 14
divide both sides by -2
y = (-1/2)x + 7 , I see that
Answered by
henry2,
4x+2y = 6.
m = -A/B = -4/2 = -2.
(2, 8).
Y = mx+b
m = -(-1/2) = 1/2.
8 = (1/2)2 + b,
b = 7.
Eq: Y = (1/2)x + 7.
m = -A/B = -4/2 = -2.
(2, 8).
Y = mx+b
m = -(-1/2) = 1/2.
8 = (1/2)2 + b,
b = 7.
Eq: Y = (1/2)x + 7.
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