Question

Solve each equation on the interval [0, 2pi):

a. 4sin^2(x)-3=0
b. cos(3x)=-1

Answer 1

(2sinx-√3)(2sinx+√3) = 0
sinx = ±√3/2
x = π/3, 2π/3, 4π/3, 5π/3

cos(3x) = -1
so 3x = π,3π,5π
x = π/3, π, 5π/3