Asked by Becca
What mass of baking soda (NaHCO3) would be required to neutralize 10.00mL of 12.1M muriatic acid remaining in a empty water bottle?
Answers
Answered by
DrBob222
muriatic acid is HCl.
HCl + NaHCO3 ==> NaCl + H2O + CO2
mols HCl = M x L = ?
mols NaHCO3 = mols HCl since 1 mol HCl reacts with 1 mol NaHCO3.
Then g NaHCO3 = mols NaHCO3 x molar mass NaHCO3.
HCl + NaHCO3 ==> NaCl + H2O + CO2
mols HCl = M x L = ?
mols NaHCO3 = mols HCl since 1 mol HCl reacts with 1 mol NaHCO3.
Then g NaHCO3 = mols NaHCO3 x molar mass NaHCO3.
Answered by
Joyce
By M x L do you mean Molarity (12.1) x Liters or moles x Liters?
Answered by
Joyce
Nevermind. I am an idiot.
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