Asked by Mateo
What mass of baking soda (NaHCO3) would be required to neutralize 10.00mL of 12.1M muriatic acid remaining in a empty water bottle?
HCl(aq)+NaHCO3(aq)=>NaCl(aq)+CO2(g)+H2O(l)
HCl(aq)+NaHCO3(aq)=>NaCl(aq)+CO2(g)+H2O(l)
Answers
Answered by
DrBob222
First you must know how much muriatic acid (HCl) remains in the empty bottle (note: if the bottle is empty there can be no HCl in the bottle.:0). Then follow the steps in this link.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
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