Asked by christine

How many grams of baking soda, NaHCO3, are needed to react with 125 mL of stomach acid having an HCl concentration of 0.05984 M?
The reaction is

NaHCO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l).


Do I need to chenage mL to L first? I'm really stuck with this question. I don't know where to start.

Answers

Answered by christine
I can solve it now. Sorry about the post.
Answered by DrBob222
Thanks for letting us know.
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