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How many grams of baking soda, NaHCO3, are needed to react with 125 mL of stomach acid having an HCl concentration of 0.05984 M?
The reaction is

NaHCO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l).


Do I need to chenage mL to L first? I'm really stuck with this question. I don't know where to start.
10 years ago

Answers

christine
I can solve it now. Sorry about the post.
10 years ago
DrBob222
Thanks for letting us know.
10 years ago

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