Asked by Anonymous
                Differentiate.
cos^-1 2x
            
            
        cos^-1 2x
Answers
                    Answered by
            bobpursley
            
    is this arccos (2x)?
or do you mean 1/(cos 2x)
    
or do you mean 1/(cos 2x)
                    Answered by
            Steve
            
    I think we can assume arccos.
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.
    
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.
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