Asked by Anonymous
Differentiate.
cos^-1 2x
cos^-1 2x
Answers
Answered by
bobpursley
is this arccos (2x)?
or do you mean 1/(cos 2x)
or do you mean 1/(cos 2x)
Answered by
Steve
I think we can assume arccos.
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.
If so, then recall that d/dx (arccos(u)) = -1/√(1-u^2) du/dx
Now just plug and chug.
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